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Question: A ray of light passes through an equilateral prism (refractive index 1.5) such that angle of inciden...

A ray of light passes through an equilateral prism (refractive index 1.5) such that angle of incidence is equal to angle of emergence and the latter is equal to 3/4th of the angle of prism. The angle of deviation is :

A

600

B

300

C

450

D

1200

Answer

300

Explanation

Solution

: Using,

Here,

∴60∘+δ=45∘+45∘⇒δ=90∘−60∘=30∘\therefore 60 ^ { \circ } + \delta = 45 ^ { \circ } + 45 ^ { \circ } \Rightarrow \delta = 90 ^ { \circ } - 60 ^ { \circ } = 30 ^ { \circ }