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Physics Question on Ray optics and optical instruments

A ray of light is incident on a plane mirror at an angle of 60∘60^\circ. The angle of deviation produced by the mirror is

A

30∘^\circ

B

60∘^\circ

C

90∘^\circ

D

120∘^\circ

Answer

60∘^\circ

Explanation

Solution

Here, angle of incidence, i=60∘i=60^{\circ} ∴\therefore Angle of deviation δ=180∘−(i+r)\delta =180^{\circ}-(i+r) =180∘−2i       ( As i=r)=180^{\circ}-2 i \,\,\,\,\,\,\, (\text { As } i=r) =180∘−2×60∘=60∘ =180^{\circ}-2 \times 60^{\circ}=60^{\circ}