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Question

Physics Question on Wave optics

A ray of light is incident at polarising angle such that its deviation is 2424^{\circ} , then angle of incidence is

A

2424^{\circ}

B

5757^{\circ}

C

6666^{\circ}

D

9090^{\circ}

Answer

5757^{\circ}

Explanation

Solution

Here, ip=r+δi_{p}=r+\delta

ip=r+24i_{p}=r+24...(i)
Moreover, ip+r=90i_{p}+r=90^{\circ}...(ii)
From Eqs. (i) and (ii), we get
ip+(ip24)=90i_{p}+\left(i_{p}-24\right) =90^{\circ}
ip=57\Rightarrow i_{p} =57^{\circ}