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Question: A ray of light is incident at 60<sup>0</sup> on a prism of refracting angle 30<sup>0</sup>. The emer...

A ray of light is incident at 600 on a prism of refracting angle 300. The emerging ray is at an angle 300 with the incident ray. The value of refractive index of the prism is –

A

3/4\sqrt { 3 } / 4

B

3/2\sqrt { 3 } / 2

C

3\sqrt { 3 }

D

232 \sqrt { 3 }

Answer

3\sqrt { 3 }

Explanation

Solution

i = 600

A = 300

d = 300

d = i + e – A

\ 30 = 60 + e – 300

\ e = 0

ray will emerge normal to the other surface

sin 600= m sin 300

m = 3\sqrt { 3 }