Question
Question: A ray of light is incident at \( 60^\circ \) on a prism of refracting angle \( 30^\circ \) . The eme...
A ray of light is incident at 60∘ on a prism of refracting angle 30∘ . The emerging ray is at an angle 30∘ with the incident ray. The value of the refractive index of the prism is?
(A) 43
(B) 23
(C) 3
(D) 32
Solution
Hint : In this question, we have to use the concept of refraction of light when it passes through a prism. The refractive index is a measure of comparing different materials. It tells how fast light can travel through a medium. Since δm is not given so we cannot use the formula μ=sin(2A)sin(A+2δm) . Instead find r1 and use the formula μ=sinr1sini1 , since i1 is given.
Complete Step By Step Answer:
Given are the following information: Incident angle i1=60∘ , Angle of prism A=30∘ , Angle of deviation(angle between incident ray and emergent ray) δ=30∘ . Let the emergent angle be i2 , refractive angle at incident plane r1 and refractive angle at emergent plane r2 as shown in the figure-
From the figure we note that i1=r1+δ1 and i2=r2+δ2 . Adding both equations we have
i1+i2=r1+r2+δ1+δ2 (1)
From △PMQ and □APNA we see that δ=δ1+δ2 and A=r1+r2 respectively
Substituting this and respective values of variables in equation 1, we get,
i1+i2=A+δ⇒i2=0∘
which further implies that
r2=0∘⇒r1=A=30∘
Using Snell’s law μ=sinr1sini1⇒μ=sin30∘sin60∘⇒μ=3
Therefore, the refractive index of the prism μ=3 .
The answer is option (C).
Note :
Don’t get confused by the term refracting angle. It is not the refractive angle at the incident plane. The angle of prism A is also called refracting angle. Also, whenever it is mentioned the angle made by emergent ray with incident ray it means the total deviation δ(=δ1+δ2) .