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Question: A ray of light is incident at \( 60^\circ \) on a prism of refracting angle \( 30^\circ \) . The eme...

A ray of light is incident at 6060^\circ on a prism of refracting angle 3030^\circ . The emerging ray is at an angle 3030^\circ with the incident ray. The value of the refractive index of the prism is?
(A) 34\dfrac{{\sqrt 3 }}{4}
(B) 32\dfrac{{\sqrt 3 }}{2}
(C) 3\sqrt 3
(D) 23\dfrac{2}{{\sqrt 3 }}

Explanation

Solution

Hint : In this question, we have to use the concept of refraction of light when it passes through a prism. The refractive index is a measure of comparing different materials. It tells how fast light can travel through a medium. Since δm{\delta _m} is not given so we cannot use the formula μ=sin(A+δm2)sin(A2)\mu = \dfrac{{\sin (A + \dfrac{{{\delta _m}}}{2})}}{{\sin (\dfrac{A}{2})}} . Instead find r1{r_1} and use the formula μ=sini1sinr1\mu = \dfrac{{\sin {i_1}}}{{\sin {r_1}}} , since i1{i_1} is given.

Complete Step By Step Answer:
Given are the following information: Incident angle i1=60{i_1} = 60^\circ , Angle of prism A=30A = 30^\circ , Angle of deviation(angle between incident ray and emergent ray) δ=30\delta = 30^\circ . Let the emergent angle be i2{i_2} , refractive angle at incident plane r1{r_1} and refractive angle at emergent plane r2{r_2} as shown in the figure-

From the figure we note that i1=r1+δ1{i_1} = {r_1} + {\delta _1} and i2=r2+δ2{i_2} = {r_2} + {\delta _2} . Adding both equations we have
i1+i2=r1+r2+δ1+δ2{i_1} + {i_2} = {r_1} + {r_2} + {\delta _1} + {\delta _2} (1)
From PMQ\vartriangle PMQ and APNA\square APNA we see that δ=δ1+δ2\delta = {\delta _1} + {\delta _2} and A=r1+r2A = {r_1} + {r_2} respectively
Substituting this and respective values of variables in equation 1, we get,
i1+i2=A+δi2=0{i_1} + {i_2} = A + \delta \Rightarrow {i_2} = 0^\circ
which further implies that
r2=0r1=A=30{r_2} = 0^\circ \Rightarrow {r_1} = A = 30^\circ
Using Snell’s law μ=sini1sinr1μ=sin60sin30μ=3\mu = \dfrac{{\sin {i_1}}}{{\sin {r_1}}} \Rightarrow \mu = \dfrac{{\sin 60^\circ }}{{\sin 30^\circ }} \Rightarrow \mu = \sqrt 3
Therefore, the refractive index of the prism μ=3\mu = \sqrt 3 .
The answer is option (C).

Note :
Don’t get confused by the term refracting angle. It is not the refractive angle at the incident plane. The angle of prism A is also called refracting angle. Also, whenever it is mentioned the angle made by emergent ray with incident ray it means the total deviation δ(=δ1+δ2)\delta ( = {\delta _1} + {\delta _2}) .