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Question: A ray of light incidents on a plane mirror at an angle of \(30{^\circ}.\) The deviation produced in ...

A ray of light incidents on a plane mirror at an angle of 30.30{^\circ}. The deviation produced in the ray is

A

3030{^\circ}

B

6060{^\circ}

C

9090{^\circ}

D

120120{^\circ}

Answer

120120{^\circ}

Explanation

Solution

δ=18060=120\delta = 180{^\circ} - 60{^\circ} = 120{^\circ}