Question
Question: A ray of light enters a diamond from air. If the refractive index of diamond is 2.42. By what percen...
A ray of light enters a diamond from air. If the refractive index of diamond is 2.42. By what percent is the speed of light reduced on entering the diamond?
Solution
First we will define a ray. Later we will discuss the refractive index in short. We will then apply a simple formula that relates speed of air in vacuum, speed of air in any other medium and the refractive index and answer this question.
Formula Used:
n=vc
Where,
n =refractive index
c =speed of light
v =phase velocity of light.
Complete step by step solution:
Have you ever been in a dark room with no lights at all when there is sunlight outside your room? What will happen when a little hole is made in the room? We will see that a little sunlight enters the room in a straight line . This is ray or in other words each of the lines in which light (and heat) may seem to stream from the sun or any luminous body when passed through a small opening.
Let us look at the refractive index: it is the ratio of the velocity of light in a vacuum to its velocity in a specified medium. Hence it is given by n=vc.
In this question it has been given that
n = 2.42
c=3×108ms−1
Using the value in the formula above,
n=vc
On substituting the values we get
2.42=v3×108
On further solving we get
v=2.423×108
⇒v=1.23×108ms−1
Speed of light in diamond is: 1.23×108ms−1
% of speed in diamond=3.8×1081.23×108×100
⇒0.3236×100
Finally we get
⇒32.36%
Thus there is 32.36% decrease in the speed of light in diamond than in air .
Note:
- Do not forget to find the percentage of refractive index decreased after finding the speed of light in diamond.
- do not write any units for refractive index and percentage found at last because, refractive index is a ratio and percentage is a mathematical operation.