Question
Question: A ray of energy 14.2 Me V is emitted from a <sup>60</sup>Co nucleus. The recoil energy of the Co nuc...
A ray of energy 14.2 Me V is emitted from a 60Co nucleus. The recoil energy of the Co nucleus is nearly
A
3 × 10-16J
B
3 × 10-15J
C
3 × 10-14J
D
3 × 10-13J
Answer
3 × 10-16J
Explanation
Solution
Pr = Pco' Pr = cE,
KE = 2mp2=2c2mcoE2
= 2×(3×108×60×1.67×10−27)(14×1.5×10−13)2 = 3 × 10-16J