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Question: A ray incident at an angle of incidence I on one surface of a prism of small angle A and emerges nor...

A ray incident at an angle of incidence I on one surface of a prism of small angle A and emerges normally from opposite surface. If the refractive index of the material opposite surface. If the refractive index of the material of prism isμ\mu, the angle of incidence I is nearly equal to:

A

Aμ\frac { \mathrm { A } } { \mu }

B

C

μA\mu \mathrm { A }

D

μA2\frac { \mu \mathrm { A } } { 2 }

Answer

μA\mu \mathrm { A }

Explanation

Solution

: As refracted ray emerges normally from opposite surface,

As A=r1+r2r1=A\mathrm { A } = \mathrm { r } _ { 1 } + \mathrm { r } _ { 2 } \quad \therefore \mathrm { r } _ { 1 } = \mathrm { A }

Now,