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Question: A ray incident at a point at an angle of incidence of 60<sup>0</sup> enter a glass sphere of refract...

A ray incident at a point at an angle of incidence of 600 enter a glass sphere of refractive index 3\sqrt { 3 } and is reflected and refracted at the farther surface of the sphere. The angle between the reflected and refracted rays at this surface is :

A

500

B

600

C

900

D

400

Answer

900

Explanation

Solution

: Refraction at P,

sin60sinr1=3\frac { \sin 60 ^ { \circ } } { \sin r _ { 1 } } = \sqrt { 3 }

or

Since,

Refraction at or

Or i2=60\mathrm { i } _ { 2 } = 60 ^ { \circ }

At point

α=180(r2+i2)=180(30+60)=90\therefore \alpha = 180 ^ { \circ } - \left( \mathrm { r } _ { 2 } ^ { \prime } + \mathrm { i } _ { 2 } \right) = 180 ^ { \circ } - \left( 30 ^ { \circ } + 60 ^ { \circ } \right) = 90 ^ { \circ }