Question
Mathematics Question on Probability Distribution
A random variable X has the following probability distribution
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(X) | 0 | k | 2k | 2k | 3k | k2 | 2k2 | 7k2+k |
then value of E(X) is:
A
1.66
B
2.66
C
3.66
D
4.66
Answer
3.66
Explanation
Solution
The correct option is(C):3.66