Question

A random variable X has the following probability distribution:

$X$	0	1	2
$P(X)$	$\frac{25}{36}$	k	$\frac{1}{36}$

If the mean of the random variable X is $\frac{1}{3}$, then the variance is

• A. $\frac{1}{18}$
• B. $\frac{5}{18}$
• C. $\frac{7}{18}$
• D. $\frac{11}{18}$

Answer 1

Answer: (B)

$\frac{5}{18}$

Answer 2

The correct answer is Option (B) : $\frac{5}{18}$