Question
Question: A railway engine of mass \(100\,tons\) is pulling a wagon of mass \(80\,tons\) with a force of \(450...
A railway engine of mass 100tons is pulling a wagon of mass 80tons with a force of 4500N. The resistance force acting is 1N per ton. The tension in the coupling between the engine and the wagon is:
(1). 1600N
(2). 2000N
(3). 200N
(4). 1500N
Solution
The system of wagon alone is not isolated as the engine exerts a force on it. So, by using Newton’s second law, its acceleration can be calculated. The tension in the coupling acts as the pulling force on the wagon, so again using Newton’s second law pulling force can be calculated.
Formulae used:
1ton=1000kg
F=ma
Complete step-by-step solution:
Given, an engine of mass 100tons is pulling a wagon of mass 80tons.
1ton=1000kg⇒80tons=8×104kg⇒100tons=105kg
The force applied to pull the wagon by the engine is 4500N.From Newton’s second law, the force is given by-
F=ma - (1)
Here,
F is the force
m is the mass
a is acceleration
The whole system of engine and wagon are moving with acceleration a, therefore,
a=m1+m2F⇒a=8×104+10×1044500⇒a=18×1044500ms−2∴a=0.025ms−2
Therefore, the system of engine and wagon are moving with acceleration of 0.025ms−2
The tension in the coupling between engine and wagon act as the pulling force on the wagon.
From eq (1), the tension is calculated as-
F=mwa
Here, mw is the mass of the wagon on which tension acts
We substitute values in the above equation to get,
F=8×104×0.025∴F=2000N
Therefore, the tension in the coupling between the engine and the wagon is 2000N.
Hence, the correct option is (2).
Note:
The Newton’s Second law says that force is required to change the state of rest or motion of a body, this means if a body is accelerating then a force acts on it. Tension is a pulling force which acts along the axis of continuous objects like string, rod etc. By Newton’s third law, it acts equal and opposite on both the objects at its ends. Convert the units as required.