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Question: A radioactive substance has a half-life of 1 year. The fraction of this material, that would remain ...

A radioactive substance has a half-life of 1 year. The fraction of this material, that would remain after 5 years will be.

A

132\frac{1}{32}

B

15\frac{1}{5}

C

12\frac{1}{2}

D

45\frac{4}{5}

Answer

132\frac{1}{32}

Explanation

Solution

Number of half lives n=51=5n = \frac{5}{1} = 5

Now NN0=(12)nNN0=(12)5=132\frac{N}{N_{0}} = \left( \frac{1}{2} \right)^{n} \Rightarrow \frac{N}{N_{0}} = \left( \frac{1}{2} \right)^{5} = \frac{1}{32}.