Question
Question: A radioactive nucleus undergoes a series of decay according to the scheme: \[A\xrightarrow{\alpha ...
A radioactive nucleus undergoes a series of decay according to the scheme:
AαA1βA2αA3γA4
If the mass number and atomic number of ‘A’ are 180 and 72 respectively, then the mass number and atomic number for A4 :
A.172 and 69
B. 174 and 70
C. 176 and 69
D. 176 and 70
Solution
Radioactive elements have a particular life, for which they undergo decay and complete their life. The half course that they complete in their life is known as their half life.
Complete answer:
We have been given a reaction sequence, where alpha, beta, and gamma particles are acting on an element. These particles in the sequence, decays the element ‘A’ four times, first the alpha particle acts, then beta particle, then again alpha particle, and at the end gamma particle results in A4.
These particles act on A and subsequently reduce their atomic number and mass number, by the times of the respective mass and atomic numbers of alpha, beta and gamma particles.
Starting from the mass number and atomic number of ‘A’, given as 180 and 72 respectively. We will reduce the mass and atomic numbers of the value of the particles from this value of A.
The mass number and atomic numbers of:
α = 4 and +2
β = 0 and -1
γ = 0 and 0, respectively. We will reduce these values from the mass and atomic number of A as,