Question

A radioactive material has a half-life of 10 days. What fraction of the material would remain after 30 days-

• A. 0.5
• B. 0.25
• C. 0.125
• D. 0.33

Answer 1

Answer: (C)

0.125

Answer 2

T_1/2 = 10 day ; t = 30 day

n = = 3 ; A. P =$\frac { 1 } { 2 ^ { 3 } }$=$\frac { 1 } { 8 }$= 0.125