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Question

Physics Question on Dual nature of matter

A radio transmitter operates at a frequency 880 kHz and a power of 10 kW. The number of photons emitted per second is

A

1.72×10311.72 \times 10^{31}

B

1.327×10251.327 \times 10^{25}

C

1.327×10371.327 \times 10^{37}

D

1.327×10451.327 \times 10^{45}

Answer

1.72×10311.72 \times 10^{31}

Explanation

Solution

No. of photons emitted per sec,
n=PowerEnergyofphotonn = \frac {Power}{Energy\, of\, photon}
=Phυ=100006.6×1034×880×103= \frac{P}{h\upsilon} = \frac{10000}{6.6 \times 10^{-34} \times 880 \times 10^{3}}
=1.72×1031= 1.72 \times 10^{31}