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Question

Physics Question on physical world

A quantity xx is given by (IFv2/WL4)(IFv^2 / WL^{4}) in terms of moment of inertia I,I, force F F, velocity v,v , work WW and Length LL. The dimensional formula for xx is same as that of :

A

Planck's constant

B

Force constant

C

Energy density

D

Coefficient of viscosity

Answer

Energy density

Explanation

Solution

x=IFV2WL4x =\frac{ IFV ^{2}}{ WL ^{4}}
[x]=[ML2][MLT2][LT1]2[ML2T2][L]4[ x ]=\frac{\left[ ML ^{2}\right]\left[ MLT ^{-2}\right]\left[ LT ^{-1}\right]^{2}}{\left[ ML ^{2} T ^{-2}\right][ L ]^{4}}
[x]=[ML1T2][ x ]=\left[ ML ^{-1} T ^{-2}\right]
[Energy density] =[EV]=\left[\frac{ E }{ V }\right]
=[ML2T2L3]=\left[\frac{ ML ^{2} T ^{-2}}{ L ^{3}}\right]
=[ML1T2]=\left[ ML ^{-1} T ^{-2}\right]
Same as xx