Question

A proton pf energy 8eV is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the sathe path will be

• A. 4e V
• B. 2e V
• C. 8e V
• D. 6e V

Answer 1

Answer: (C)

8e V

Answer 2

$Bqv=\frac{mv^2}{r}$ $Bq =\frac{mv}{r}=\frac{p}{r}$ $E_k=\frac{q^2\,r^2\,b^2}{2m}$ $E_k\,\propto \frac{q^2}{m}$ $\frac{E_{K_o}}{E_{K_p}}\propto \frac{q^2_o}{q^2_p}\times \frac{m_p}{m_d}$