Question
Question: A proton (mass \(= 1.67 \times 10 ^ { - 27 } \mathrm {~kg}\) and charge \(3.4 \times 10 ^ { 7 } \mat...
A proton (mass =1.67×10−27 kg and charge 3.4×107 m/sec. The acceleration of the proton should be
A
6.5×1015 m/sec2
B
6.5×1013 m/sec2
C
6.5×1011 m/sec2
D
6.5×109 m/sec2
Answer
6.5×1015 m/sec2
Explanation
Solution
F = ma = qvB ⇒ a=mqvB=1.67×10−271.6×10−19×2×3.4×107
= 6.5 × 1015m/sec2