Question

A proton in a cyclotron changes its velocity from 30 km/s north to 40 km/s east in 20 sec. What is the average acceleration during this time?

• A. 2.5 km/s² at $37^{0}$E of S
• B. 2.5 km/s² at $37^{0}$ S of E
• C. 2.5 km/s²at $37^{0}$ N of E
• D. 2.5 km/s² at $37^{0}$ E of N

Answer 1

Answer: (B)

2.5 km/s² at $37^{0}$ S of E

Answer 2

$\overrightarrow{a} = \frac{40\widehat{i} - 30\widehat{j}}{20}$