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Question

Question: A proton enters a magnetic field of flux density \(2 \times 10 ^ { 7 } \mathrm {~m} / \mathrm { sec ...

A proton enters a magnetic field of flux density 2×107 m/sec2 \times 10 ^ { 7 } \mathrm {~m} / \mathrm { sec } at an angle of 3030 ^ { \circ } with the field. The force on the proton will be

A

B

C

D

Answer

Explanation

Solution

F=qvBsinθF = q v B \sin \theta