Question

A proton and ana-particle are accelerated through a potential difference of 100 V. The ratio of the wavelength associated with the proton to that associated with an a-particle is –

• A. $\sqrt{2}$: 1
• B. 2 : 1
• C. $2\sqrt{2}$: 1
• D. $\frac{1}{2\sqrt{2}}$ : 1

Answer 1

Answer: (C)

$2\sqrt{2}$: 1

Answer 2

DV = same

l µ $\frac{1}{\sqrt{qm_{0}}}$

$\frac{\lambda_{p}}{\lambda_{\alpha}}$ = $\sqrt{\frac{q_{\alpha}m_{\alpha}}{q_{p}m_{p}}}$ = $\sqrt{\frac{(2e)(4m_{p})}{(e)m_{p}}}$

= 2 $\sqrt{2}$ : 1