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Question: A proton and an alpha-particle enter a uniform magnetic field with the same velocity. The period of ...

A proton and an alpha-particle enter a uniform magnetic field with the same velocity. The period of rotation of the alpha particle will be –

A

Four times that of the proton

B

Two times that of the proton

C

Three times that of the proton

D

Same as that of the proton

Answer

Two times that of the proton

Explanation

Solution

T = 2πmBq\frac{2\pi m}{Bq}; Tµmq\frac{m}{q} Ž TαTp=mαqα×qpmp=42=21\frac{T_{\alpha}}{T_{p}} = \frac{m_{\alpha}}{q_{\alpha}} \times \frac{q_{p}}{m_{p}} = \frac{4}{2} = \frac{2}{1}

Ta = 2Tp