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Question: A proton, a deutron and a a-particle having the same kinetic energy are moving in circular trajector...

A proton, a deutron and a a-particle having the same kinetic energy are moving in circular trajectories in a constant magnetic field. If rp, rd and ra denoted respectively be the radii of trajectory of those particles. Then-

A

ra = rp<rd

B

ra>rd>rp

C

ra = rd>rp

D

rp = rd= ra

Answer

ra = rp<rd

Explanation

Solution

r = 2m(KE)qB\frac{\sqrt{2m(KE)}}{qB}