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Question: A proton, a deuteron and an alpha particle are moving with the same kinetic energies and enter a per...

A proton, a deuteron and an alpha particle are moving with the same kinetic energies and enter a perpendicular magnetic field. Then the ratio of the radii of their circular paths will be-

A

2 : 2 : 1

B

1 : 2\sqrt { 2 } : 1

C

1 :2\sqrt { 2 } : 2

D

2\sqrt { 2 } : 2\sqrt { 2 } : 1

Answer

1 : 2\sqrt { 2 } : 1

Explanation

Solution

r = 2 m(KE)9 B\frac { \sqrt { 2 \mathrm {~m} ( \mathrm { KE } ) } } { 9 \mathrm {~B} }