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Question

Physics Question on Kinetic Energy

A proton, a deuteron and an α-particle with same kinetic energy enter into a uniform magnetic field at right angle to magnetic field. The ratio of the radii of their respective circular paths is :

A

1:2:21 : \sqrt2 : \sqrt2

B

1:1:21 : 1 : \sqrt2

C

2:1:1\sqrt2 : 1 : 1

D

1:2:11 : \sqrt2 : 1

Answer

1:2:11 : \sqrt2 : 1

Explanation

Solution

r=mvqBr = \frac{mv}{qB}

= 2m(KE)qB\frac{\sqrt{2m(KE)}}{qB}

r1:r2:r3=m1q1:m2q2:m3q3r_1: r_2: r_3 = \frac{\sqrt m_1}{q_1} : \frac{\sqrt m_2}{q_2} : \frac{\sqrt m_3}{q_3}

= 11:21:42\frac{\sqrt 1}{1}:\frac{\sqrt 2}{1}:\frac{\sqrt 4}{2}

= 1:2:11: \sqrt2 : 1