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Question

Question: A projectile thrown with a speed \(v\) at an angle \(\theta\) has a range \(R\) on the surface of ea...

A projectile thrown with a speed vv at an angle θ\theta has a range RR on the surface of earth. For same vv and θ\theta, its range on the surface of moon will be

A

R/6R/6

B

6R\mathbf{6R}

C

R/36R/36

D

36R36R

Answer

6R\mathbf{6R}

Explanation

Solution

Range is given by R=u2sin2θgR = \frac{u^{2}\sin 2\theta}{g}

On moon gm=g6g_{m} = \frac{g}{6}. Hence Rm=6RR_{m} = 6R