Question

A projectile thrown with a speed v at an angle θ has a range R on the surface of earth. For same v and θ, its range on the surface of moon will be

• A. R/6
• B. 6 R
• C. R/36
• D. 36 R

Answer 1

Answer: (B)

6 R

Answer 2

$R = \frac{u^{2}\sin 2\theta}{g}$ $\therefore R \propto 1/g$

$\frac{R_{Moon}}{R_{Earth}} = \frac{g_{Earth}}{g_{Moon}}$= 6 $\left\lbrack \because g_{Moon} = \frac{1}{6}g_{Earth} \right\rbrack$

$\therefore R_{Moon} = 6R_{Earth} = 6R$