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Question: A projectile is projected with some velocity whose horizontal component is u<sub>x</sub>, Distance b...

A projectile is projected with some velocity whose horizontal component is ux, Distance between the points where it has a vertical velocity equal to ±vy will be –

A

vyuxg\frac{v_{y}u_{x}}{g}

B

2vy2g\frac{2v_{y}^{2}}{g}

C

2ux2g\frac{2u_{x}^{2}}{g}

D

2vyuxg\frac{2v_{y}u_{x}}{g}

Answer

2vyuxg\frac{2v_{y}u_{x}}{g}

Explanation

Solution

R = 2uxvyg\frac { 2 u _ { x } v _ { y } } { g }