Question
Question: A projectile is given an initial velocity of \(\widehat{i} + 2\widehat{j}\). The Cartesian equation ...
A projectile is given an initial velocity of i+2j. The Cartesian equation of its path is - (g = 10 m/s2)
A
y = 2x – 5x2
B
y = x – 5x2
C
4y = 2x – 5x2
D
y = 2x – 25x2
Answer
y = 2x – 5x2
Explanation
Solution
u=i+2j^
y = x tan q – 2u2cos2θgx2
or y = x. uxuy−2⋅ux2gx2
or y = x (12)−2.(1)2gx2 \ y = 2x – 5x2