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Question: A projectile is given an initial velocity of \(\widehat{i} + 2\widehat{j}\). The Cartesian equation ...

A projectile is given an initial velocity of i^+2j^\widehat{i} + 2\widehat{j}. The Cartesian equation of its path is - (g = 10 m/s2)

A

y = 2x – 5x2

B

y = x – 5x2

C

4y = 2x – 5x2

D

y = 2x – 25x2

Answer

y = 2x – 5x2

Explanation

Solution

u=i+2j^\vec { u } = i + 2 \hat { j }

y = x tan q – gx22u2cos2θ\frac { \mathrm { gx } ^ { 2 } } { 2 \mathrm { u } ^ { 2 } \cos ^ { 2 } \theta }

or y = x. uyuxgx22ux2\frac { u _ { y } } { u _ { x } } - \frac { g x ^ { 2 } } { 2 \cdot u _ { x } ^ { 2 } }

or y = x (21)gx22.(1)2\left( \frac { 2 } { 1 } \right) - \frac { \mathrm { gx } ^ { 2 } } { 2 . ( 1 ) ^ { 2 } } \ y = 2x – 5x2