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Physics Question on projectile motion

A projectile is fired from horizontal ground with speed vv and projection angle θ\theta When the acceleration due to gravity is gg, the range of the projectile is dd If at the highest point in its trajectory, the projectile enters a different region where the effective acceleration due to gravity is g=g081g^{\prime}=\frac{g}{081}, then the new range is d=ndd^{\prime}=n d The value of nn is ___

Answer

The value of nn is 0.95.\underline{0.95}.