Question
Question: A projectile has a range of \[50m\] and reaches a maximum height of \[10m\] calculating the angle at...
A projectile has a range of 50m and reaches a maximum height of 10m calculating the angle at which the projectile is fired.
A. tan153
B. tan−152
C. tan−173
D. tan−154
Solution
The study of the motion of an object under gravity is called projectile motion. The height at which the speed of the object becomes zero from the ground is called the maximum height attained by the projectile. The formula for the range of a projectile is needed here. Then the value of the initial velocity has to be calculated. From these, the required angle can be found.
Complete step by step solution:
Let us first write the information given in the question.
Range of projectile = 50m, maximum height = 10m
We have to calculate the angle at which the projectile is fired.
The maximum height of the projectile is given by the following formula.
H=2gu2sin2θ……………..(1)
Here, u is the initial speed of the projectile, g is the acceleration due to gravity, and θ is the angle of projection.
Now, the formula for the range of a projectile is also given below.
R=gu2sin2θ
From this, we can find the value of initial velocity.
u2=sin2θRg
Let us substitute this value in equation (1).
H=(sin2θRg)2gsin2θ=4sinθcosθR×sin2θ⇒H=4cosθRsinθ=4Rtanθ
Let us now put the values in the above formula.
10=450tanθ⇒tanθ=54
θ=tan−1(54)⇒θ=57o
Therefore, the angle of projection is 57o
Hence, the correct option is (D) tan−154.
Note:
The speed with which an object is projected is the same speed with which the object has when it reaches the ground.
The study of the projectile is done based on three quantities namely, range, time of flight, and maximum height attained by the projectile.
The range is the horizontal distance covered by the projectile from the initial point.
Time of flight is the time taken by the projectile to cover the whole path/range.