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Question

Chemistry Question on Thermodynamics

A process is spontaneous at a given temperature if

A

ΔH=0,ΔS<0\Delta H = 0,\Delta S < 0

B

ΔH>0,ΔS<0\Delta H > 0,\Delta S < 0

C

ΔH<0,ΔS>0\Delta H < 0,\Delta S > 0

D

ΔH>0,ΔS=0\Delta H > 0,\Delta S = 0

Answer

ΔH<0,ΔS>0\Delta H < 0,\Delta S > 0

Explanation

Solution

ΔG=ΔHTΔS\Delta G = \Delta H - T \Delta S A process is spontaneous if ΔG\Delta G is -ve and ΔG\Delta G will be -ve when ΔH\Delta H is -ve and ΔS\Delta S is positive.