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Question

Question: A problem of mathematics is given to three students whose chances of solving the problem are 1/3, 1...

A problem of mathematics is given to three students whose

chances of solving the problem are 1/3, 1/4 and 1/5 respectively. The probability that the question will be solved is

A

2/3

B

¾

C

4/5

D

3/5

Answer

3/5

Explanation

Solution

The probabilities of students not solving the problem are 113=23,114=341 - \frac { 1 } { 3 } = \frac { 2 } { 3 } , 1 - \frac { 1 } { 4 } = \frac { 3 } { 4 } and 115=451 - \frac { 1 } { 5 } = \frac { 4 } { 5 } .

Therefore the probability that the problem is not solved by any one of them =23×34×45=25= \frac { 2 } { 3 } \times \frac { 3 } { 4 } \times \frac { 4 } { 5 } = \frac { 2 } { 5 } .

Hence, the probability that problem is solved=125=35= 1 - \frac { 2 } { 5 } = \frac { 3 } { 5 }.