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Question

Physics Question on Ray optics and optical instruments

A prism with a refracting angle 3030^{\circ}, made of material of refractive index 1.732, has one of its faces silvered. A ray of light incident at a certain angle on the other face retraces the path after getting reflected at the silvered face. The angle of incidence is

A

3030^{\circ}

B

4545^{\circ}

C

6060^{\circ}

D

1515^{\circ}

Answer

6060^{\circ}

Explanation

Solution

Refracting angle of prism, A=30μ=1.732,i=?A = 30^{\circ} \, \mu = 1.732, i = ?
r=9060=30r = 90^{\circ} - 60^{\circ} = 30^{\circ}
Using Snell's law at point PP,
1.sini=μsinr1 .\sin i = \mu \sin r
sini=1.732×sin30=1.7322=sin60\sin i = 1.732 \times \sin 30^{\circ} = \frac{1.732}{2} = \sin 60^{\circ}
or, i=60i = 60^{\circ}