A prism has a refracting angle of ( 60{}^\circ ) . If it pro... | Physics | SolveeIt | Solveeit

Today, August 18

Question

A prism has a refracting angle of $60{}^\circ$ . If it produces a minimum deviation of $30{}^\circ$ in an incident ray, the angle of incidence is

A

$15{}^\circ$

B

$30{}^\circ$

C

$45{}^\circ$

D

$60{}^\circ$

Answer

$45{}^\circ$

Explanation

Solution

Given: angle of prism $A=60^{\circ}$ , minimum deviation $\delta_{m}=30^{\circ}$ $\therefore$ Angle of incidence $i =\frac{A+\delta_{m}}{2}$ $=\frac{60^{\circ}+30^{\circ}}{2}=45^{\circ}$