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Question: A power transformer is used to step up an alternating e.m.f. of 220 V to 11 kV to transmit 4.4 kW of...

A power transformer is used to step up an alternating e.m.f. of 220 V to 11 kV to transmit 4.4 kW of power. If the primary coil has 1000 turns, what is the current rating of the secondary? Assume 100% efficiency for the transformer

A

4 A

B

0.4 A

C

0.04 A

D

0.2 A

Answer

0.4 A

Explanation

Solution

is=PsVs=4.4×10311×103=0.46muAi_{s} = \frac{P_{s}}{V_{s}} = \frac{4.4 \times 10^{3}}{11 \times 10^{3}} = 0.4\mspace{6mu} A