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Question

Physics Question on Current electricity

A potentiometer wire ABAB having length LL and resistance 12r12\, r is joined to a cell DD of emf ε\varepsilon and internal resistance rr. A cell CC having emfε/2emf \, \varepsilon /2 and internal resistance 3r3r is connected. The length AJAJ at which the galvanometer as shown in fig. shows no deflection is :

A

512\frac{5}{12} L

B

1124\frac{11}{24} L

C

1112\frac{11}{12} L

D

1324\frac{13}{24} L

Answer

1324\frac{13}{24} L

Explanation

Solution

i=ε13ri = \frac{\varepsilon}{13r}
i(xL12r)=ε2i\left(\frac{x}{L} 12r\right) = \frac{\varepsilon}{2}
ε13r[xL.12r]=ε2x=13L24\frac{\varepsilon}{13r} \left[\frac{x}{L} .12r\right] = \frac{\varepsilon}{2} \Rightarrow x = \frac{13L}{24}