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Question: A potential barrier of \(0.3V\) exists across a p – n junction if the depletion region is \(1\mu m\)...

A potential barrier of 0.3V0.3V exists across a p – n junction if the depletion region is 1μm1\mu m wide, what is the intensity of electric field in this region?

A

2×105Vm−12 \times 10^{5}Vm^{- 1}

B

3×105Vm−13 \times 10^{5}Vm^{- 1}

C

4×105Vm−14 \times 10^{5}Vm^{- 1}

D

5×105Vm−15 \times 10^{5}Vm^{- 1}

Answer

3×105Vm−13 \times 10^{5}Vm^{- 1}

Explanation

Solution

: Electric field

E=Vd=0.31×10−6=3×105Vm−1E = \frac{V}{d} = \frac{0.3}{1 \times 10^{- 6}} = 3 \times 10^{5}Vm^{- 1}