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Question

Physics Question on Semiconductor electronics: materials, devices and simple circuits

A potential barrier of 0.4 V exists across a p-n junction. An electron enters the junction from the n-side with a speed of 6.0 × 105 ms–1. The speed with which electrons enters the p side will be
x3×105\frac{x}{3} × 10^5 ms-1
the value of x is _________.
(Give mass of electron = 9 × 10–31 kg, charge on electron = 1.6 × 10–19 C)

Answer

The correct answer is 14
Conserving energy,
12mv2=12m(6×105)20.4eV\frac{1}{2} mv² = \frac{1}{2} m ( 6 × 10^5)^2 - 0.4eV
v=(6×105)22×1.6×1019×0.49×1031⇒ v = \sqrt{( 6 × 10^5)^2 - \frac{2 × 1.6 × 10^{-19} × 0.4}{9 × 10^{-31} }}
=36×10101.289×1012=\sqrt{36 × 10^{10} - \frac{1.28}{9} × 10^{12}}
v=143×105m/s⇒ v = \frac{14}{3} × 10^5 m/s
⇒ x = 14
There , the speed will be 14 m/s