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Question: A police jeep is chasing with, velocity of 45 km/h a thief in another jeep moving with velocity 153 ...

A police jeep is chasing with, velocity of 45 km/h a thief in another jeep moving with velocity 153 km/h. Police fires a bullet with muzzle velocity of 180 m/s. The velocity it will strike the car of the thief is

A

150 m/s

B

27 m/s

C

450 m/s

D

250 m/s

Answer

150 m/s

Explanation

Solution

Effective speed of the bullet

= speed of bullet + speed of police jeep

=1806mum/s+456mukm/h=(180+12.5)6mum/s=192.56mum/s= 180 ⥂ \mspace{6mu} m/s + 45\mspace{6mu} km/h = (180 + 12.5)\mspace{6mu} m/s = 192.5\mspace{6mu} m/s

Speed of thief ’s jeep =153km/h=42.5m/s= 153km/h = 42.5m/s

Velocity of bullet w.r.t thief ’s car=192.542.5= 192.5 - 42.5=150m/s