Question

A pole stands vertically inside a triangular park ∆ABC. If the angle of elevation of the top of

the pole from each corner of the park is same, then in ∆ ABC the foot of the pole is at the

• A. Centroid
• B. Circumcentre
• C. Incentre
• D. Orthocentre

Answer 1

Answer: (B)

Circumcentre

Answer 2

Let PQ be the pole, since the angle of Q from each of the points A, B, C is the same = θ.

$P A = P B = P C = h \cot \theta$

Since P is equidistant from A, B, C.

P is circumcentre of $\Delta$ ABC