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Question

Physics Question on Refraction of Light

A point source of light is placed 4m4 \,m below the surface of water of refractive index 53\frac{5}{3}. The minimum diameter of a disc, which should be placed over the source, on the surface of water to cut-off all right coming out of water is

A

infinite

B

6 m

C

4 m

D

3 m

Answer

6 m

Explanation

Solution

Light from the source goes in all directions, forming an angle of incidence to the surface of water. For angles greater than a critical angle, the light rays reflect back into the water. The critical angle =θc=sin11μ=sin135=\theta_{c}=\sin ^{-1} \frac{1}{\mu}=\sin ^{-1} \frac{3}{5} Thus, the radius of the disc required =h×tanθc=4×34m=3m= h \times \tan \theta_{ c }=4 \times \frac{3}{4} m =3\, m Hence, the diameter of the disc =6m=6 \,m