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Question

Physics Question on sound

A point source emits sound equally in all directions in a non-absorbing medium. Two point P and Q are at distances of 2 m and 3 m respectively from the source. The ratio of the intensities of the waves at P and Q is

A

9:49 : 4

B

2:32:3

C

3:23:2

D

4:94 : 9

Answer

9:49 : 4

Explanation

Solution

Intensity =energytime×area=powerarea= \frac{energy}{time \times area}=\frac{power}{area} From a point source energy spread over the surfaceof sphere of radius rr \therefore Intensity I=PA=P4πr21r2I=\frac{P}{A}=\frac{P}{4\pi r^{2}}\propto\frac{1}{r^{2}} I1I2=(r2r1)2=(32)2\frac{I_{1}}{I_{2}}=\left(\frac{r_{2}}{r_{1}}\right)^{2}=\left(\frac{3}{2}\right)^{2} I1I2=94\therefore \frac{I_{1}}{I_{2}}=\frac{9}{4}