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Question

Physics Question on electrostatic potential and capacitance

A point Q lies on the perpendicular bisector of an electrical dipole of dipole moment p. If the distance of Q from the dipole is r (much larger than the size of the dipole), then the electric field at Q is proportional to

A

p2 p^2 and r3r^{ - 3}

B

p and r2 r^{ - 2}

C

p1p^{ - 1} and r2r^{ - 2}

D

p and r3 r^{-3}

Answer

p and r3 r^{-3}

Explanation

Solution

he electric field at a point on equatorial line (perpendicular bisector) of dipole at a distance r is given by, E = P4πε01(r2+a2)3/2\frac{ P}{ 4 \pi \varepsilon_0} \cdot \frac{1}{ (r^2 + a^2)^{ 3/2} }
where 2 a = length of dipole ( ( \because r > > a)
E=P4πε01r3\therefore E = \frac{ P}{ 4 \pi \varepsilon_0} \cdot \frac{1}{ r^3 } \cdot i, e., E \propto p and E r3 \propto r^{ - 3}.