Question

A point $P$ moves so that the sum of squares of its distances from the points $(1,2)$ and $(-2,1)$ is $14$. Let $f(x, y)=0$ be the locus of $P$, which intersects the $x$-axis at the points $A , B$ and the $y$-axis at the point $C, D$. Then the area of the quadrilateral $ACBD$ is equal to

• A. $\frac{9}{2}$
• B. $\frac{3 \sqrt{17}}{2}$
• C. $\frac{3 \sqrt{17}}{4}$
• D. $9$

Answer 1

Answer: (B)

$\frac{3 \sqrt{17}}{2}$

Answer 2

The correct option is (B): $\frac{3 \sqrt{17}}{2}$