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Question

Physics Question on rotational motion

A point P consider at contact point of a wheel on ground which rolls on ground without slipping then value of displacement of point P when wheel completes half of rotation (If radius of wheel is 1m) :

A

2m

B

π2+4\sqrt{\pi^2+4} m

C

π\pi m

D

π2+2\sqrt{π^2+2} m

Answer

π2+4\sqrt{\pi^2+4} m

Explanation

Solution

The correct option is (B) : π2+4\sqrt{\pi^2+4} m

displacement PQ = PM2\sqrt{PM^2}+(QM)2=πR2+(2R)2\sqrt {\pi R^2 +(2R)^2} =π2+4\sqrt{\pi^2+4} (∵ R = 1m)