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Question: A point on parabola \({y^2} = 18x\) at which the ordinate increases at twice the rate of the absciss...

A point on parabola y2=18x{y^2} = 18x at which the ordinate increases at twice the rate of the abscissa is:

A.(98,92) B.(2,4) C.(98,92) D.(2,4)  A.\left( {\dfrac{9}{8},\dfrac{9}{2}} \right) \\\ B.\left( {2, - 4} \right) \\\ C.\left( {\dfrac{{ - 9}}{8},\dfrac{9}{2}} \right) \\\ D.\left( {2,4} \right) \\\
Explanation

Solution

Hint: Differentiate the given curve equation and equate with the curve equation to find the points.
Given that:
Curve equation y2=18x{y^2} = 18x
Ordinate increases twice the abscissa
So, dydx=2\dfrac{{dy}}{{dx}} = 2 -- (1)
Differentiating the given parabola equation we get
2ydy=18dx dydx=182y  2ydy = 18dx \\\ \dfrac{{dy}}{{dx}} = \dfrac{{18}}{{2y}} \\\ --- (2)
From equation 1 and 2, we have
182y=2 y=92  \dfrac{{18}}{{2y}} = 2 \\\ y = \dfrac{9}{2} \\\
Substituting the value of yy obtained in the given curve equation:
y2=18x 814=18x x=98  \Rightarrow {y^2} = 18x \\\ \Rightarrow \dfrac{{81}}{4} = 18x \\\ \Rightarrow x = \dfrac{9}{8} \\\
Hence, the point is (98,92)\left( {\dfrac{9}{8},\dfrac{9}{2}} \right)
Correct answer is option A.

Note:The following curve given in the question represents a parabola about x-axis. The parabola is the locus of points in that plane that are equidistant from both the directrix and the focus.