Question

A point object O is placed in front of a glass rod having spherical end of radius of curvature 30 cm. The image would be formed at –

• A. 30 cm left
• B. Infinity
• C. 1 cm to the right
• D. 18 cm to the left

Answer 1

Answer: (A)

30 cm left

Answer 2

u = – 15 cm , R = + 30 cm

µ = 1.5 = $\frac { 3 } { 2 }$, µ₁ = 1

– =

– $\frac { 1 } { - 15 }$ = $\frac { 3 / 2 - 1 } { + 30 }$

= $\frac { 1 } { 60 }$ – $\frac { 4 } { 60 }$ = = $\frac { - 3 } { 60 }$

Ž left side